x^2-4.9x+2.2=0

Solution for x^2-4.9x+2.2=0 equation:

x^2-4.9x+2.2=0

a = 1; b = -4.9; c = +2.2;
Δ = b2-4ac
Δ = -4.92-4·1·2.2
Δ = 15.21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.9)-\sqrt{15.21}}{2*1}=\frac{4.9-\sqrt{15.21}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.9)+\sqrt{15.21}}{2*1}=\frac{4.9+\sqrt{15.21}}{2}
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